Calculate the molarity of a solution that contains 14.60 grams of Na2CO3 in 875.00 mL of solution.
What is the final molarity when 80.00 mL of a 1.173-M HNO3 solution is diluted to 590.00 mL?
molar mass =105.9888 g/mol
moles in solution= 14.60/105.9888=0.138moles
molarity= 875*0.138/1000= 0.121 M
2. final molarity= 80*1.173/590=0.159M
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