can some one please help me please fast fast

Chemistry
Tutor: None Selected Time limit: 1 Day

1,Calculate the molarity of the solution that contains 18.8 g of KOH in 734 mL of solution. 

2,What volume, in milliliters, of a 1.990 M solution of KMnO4 is needed to provide 115 grams of solute? 

Mar 3rd, 2015

1) molarity=moles of solute/liters of solution. Molar mass of KOH=56.12. Total moles of KOH=18.8g x 1mol/56.12g=.335 moles. Total mL of solution 734mL x 1L/1000mL= .734L. molarity=.335moles/.734L=.456M

2) molarity=1.990M KMnO4 molar mass= 158.03g/mol. Total moles of KMnO4=115g x 1mol/158.03g=.728mol.

1.990M=.728mol/ #of liters #of liters= 0.365L. # of milliliters=365mL 

Mar 3rd, 2015

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Mar 3rd, 2015
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Mar 3rd, 2015
Dec 8th, 2016
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