The Ka for HF is 6.9 x 10^-4. What is the value of Kb for F-?

Use the identity...

kw = ka * kb

where kw is the dissociation constant for water, kw = 1.0E-14

Solve for kb...

kb = kw / ka

= (1.0 E-14) / (6.9E-4)

=1.4 E -11 (with sigfigs in mind)

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