The Ka for HF is 6.9 x 10^-4. What is the value of Kb for F-?
Use the identity...
kw = ka * kb
where kw is the dissociation constant for water, kw = 1.0E-14
Solve for kb...
kb = kw / ka
= (1.0 E-14) / (6.9E-4)
=1.4 E -11 (with sigfigs in mind)
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