405 tenth graders 349 can read above 8th grade level p=0.138. Construct the 90% confidence interval for population proportion of 10th graders at or below 8th grade readings even lower bound and higher bound round to 3 decimal places
estimate = 56/405 = 0.138
standard error = sqrt(p*(1-p)/n) = sqrt(0.138*0.862/405) =0.0171
Tabular value for 90% is 1.645
90% Confidence interval = 0.138-1.645*0.0171, 0.138+1.645*0.0171
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