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##### Another question stumping me..

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Thanksgiving's coming up and Harveys turkey farm sold 100 gobblers to Oscar Meyer for their famous turkey-dogs. Oscar meyer found that 90 of the gobblers were in reality duck. Find a 90% confidence interval for true proportion of turkeys Harvey owns.

Mar 5th, 2015

Sigma for sample = sq rt. ( pt x pg/100. = 0.03

90% Confidence : z = 1.645

C. I. = 0.9 + or minus (1.645 x 0.03)

= 0.949 or 0.85

Answer C. I. = 0.9 + or - 0.049

Mar 5th, 2015

how do I find the standard deviation?

Mar 5th, 2015

Standard deviation is sigma for sample in the first line above where pt and pg are proportion for turkey and gobbler.

Mar 5th, 2015

is there any way that I can prove that an SRS was used in this??

Mar 5th, 2015

and since 90 of the 100 weren't turkeys and actually duck , shouldn't it be .1 +/- (1.645x.03) instead of  0.9 +/- (1.645 x 0.03)?

Mar 5th, 2015

Selection of 10 turkeys out of 100 is the simple random sample because each object had equal chance of being selected.

Mar 5th, 2015

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Mar 5th, 2015
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Mar 5th, 2015
Sep 21st, 2017
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