Based on Kepler's third law:

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Mplanet = a3/P2, calculate the mass of an unknown planet if its moon's period is 0.058 years and semimajor axis is 0.03 AU. How many times more or less massive is this planet than the Earth? (Use 1 Earth Mass = 3x10-6 Solar Masses).

Mar 6th, 2015

Using Mplanet = a^3/P^2 = 0.03^3 / 0.058^2 = 0.0080 Solar masses

This is 0.0080/(3x10^-6) = 2675.4 times more massive than Earth.

Mar 6th, 2015

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Mar 6th, 2015
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Mar 6th, 2015
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