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How many moles of PCl5 can be produced from 21.0g of P4 (and excess Cl2)?

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How many moles of 

PCl5 can be produced from 21.0g of P4 (and excess Cl2)?
Oct 23rd, 2017

Answer:

here we have:

21/132 = 0.159 mols of P4

so we get 0.159 mols of PCl5

I think that the global reaction involves 1 mol of P4  and 1 mol of PCl5


Mar 6th, 2015

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Oct 23rd, 2017
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Oct 23rd, 2017
Oct 24th, 2017
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