Statistics questions t value is 2.412

Statistics
Tutor: None Selected Time limit: 1 Day

Mar 9th, 2015

Assuming we're using the t-distribution (in practice we shouldn't have to, since the sample size is high!) we have:

Standard error = sd / sqrt(n)

= 0.0511/sqrt(46)

= 0.007534

The confidence interval will be given by:

mean +/- t_crit * Standard error

= 0.307 +/- 2.412*0.007534

= 0.289 to 0.325

Mar 9th, 2015

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Mar 9th, 2015
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Mar 9th, 2015
Dec 3rd, 2016
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