g(x) = 3x^{2} − 24x + 49

(c) Find its maximum or minimum value.

Is this a maximum or minimum value?

x coordinate of the vertex = -b/2a

x = 24 / 2*3 = 24 / 6 = 4

y = 3(4^2) - 24*4 + 49 = 48 -96 +49 = 1

Vertex (4, 1)

Minimum value because a is positive meaning that the parabola opens up.

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