### Question Description

determine how the parabola has in common with the x-axis and whether its vertex lies above on or below the x-axis

y=4x^2-12x+12

## Final Answer

Answer:

here we can rewrite your quadratic function as below:

y = 4 (x-3/2)^2 +3

so the vertex is V = (3/2, 3)

that parabola doesn't intersect the x-axis

the discriminant is negative:

discriminant = 36 - 48 = -12

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