determine how many points parobola has in common with x axis and whether its vertex lies above on or below the x-axis
1 point in common vertex on x-axis
2 points in common vertex below x-axis
2 points in common vertex above x-axis
no points in
here we can rewrite your quadratic equation as follows:
y = -2 (x- 1/4)^2 - 23/8
and the vertex is:
V = (1/4, -23/8)
so the vertex is below the x-axis
and we have no point in common with the x-axis
so the fourth option
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