determine how many points parobola has in common with x axis and whether its vertex lies above on or below the x-axis

y=-2x^2+x-3

1 point in common vertex on x-axis

2 points in common vertex below x-axis

2 points in common vertex above x-axis

no points in

Answer:

here we can rewrite your quadratic equation as follows:

y = -2 (x- 1/4)^2 - 23/8

and the vertex is:

V = (1/4, -23/8)

so the vertex is below the x-axis

and we have no point in common with the x-axis

so the fourth option

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