determine how many points the parabola has in common with the x-axis and whether its vertex lies above, on , or below the x -axis
-first consider what is means to touch the x-axis: being not the x-axis means that y is equal to zero.
-so you set up an equation were 0=-2x^2+x-3
-and the right side is factorable (-2x+3)(x+1) they are two distinct factors thus two answers when y=0 thus two point in common with the x-axis
-Notice that the number in front of the x^2. It is a negative number so it means that it is making an "n" shape and not an "u" shape.
-if it is an n shaped and the it crosses the x-axis twice, the vertex has to be above the axis. Because if it was below it will never cross the x-axis.
Hope this helps :)
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