without drawing the graph of the equation, determine how many points the parabo.

label Algebra
account_circle Unassigned
schedule 1 Day
account_balance_wallet $5

determine how many points the parabola has in common with the x-axis and whether its vetex lies above on or below the x axis.

y=-2x^2+x-3

Mar 10th, 2015

We can see from the fact that x^2 term is negative that the parabola goes to -infinity as |x| gets large (it forms an inverted-u shape).

We can also rearrange this standard form quadratic (y = ax^2 + bx + c) into vertex form (y = a(x - h)^2 + k):

y=-2x^2+x-3

= -2(x^2 -x/2 +3/2)

= -2(x - 1/4)^2 + 3/2-1/16

Since (h,k) is the vertex we just need to check whether k is positive or negative. It is positive, so the vertex lies above the x-axis. And since the parabola curves down, it will cross the x-axis at two points.

Mar 10th, 2015

Studypool's Notebank makes it easy to buy and sell old notes, study guides, reviews, etc.
Click to visit
The Notebank
...
Mar 10th, 2015
...
Mar 10th, 2015
Jun 28th, 2017
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer