A normally distributed population has mean 57.7 and standard deviation 12.1
Find the probability that the mean of a sample of size 16 drawn from this population is less than 45
The sample mean is the population mean: 57.7.
The standard deviation of the sample mean (called the "standard error") is
population standard deviation / sqrt(sample size)
= 12.1 / sqrt(16)
= Norm.cdf( x, mean, sd )
= Norm.cdf( 45, 57.7, 3.025 )
= 1.34435 x 10^-05
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