1) Solubility product of lead(II) fluoride is 3.7x10^-8. Estimate solubility of the salt.
2) Does precipitate of barium fluoride form when 100 mL of 1.0x10^-3 M Ba(NO3)2(aq) is mixed w/ 200mL of 1.0x10^-3M KF(aq)? Ignore possible protonation of F-.
Answer to first question
PbF2(s) ⇋ Pb+(aq) + 2F-(aq)The Ksp expression is
Ksp = [Pb2+][F-]2 = 3.7 x 10^-8
Let solubility of Pb2+ be S
therfore solubility of F- is 2S
S * (2S)^2 = Ksp
S^3= 0.925 *10 ^ -8
S^3 =9.25 * 10^-9
S=2.1 * 10^-3
For second question, calculate the concentrations and find solubility product. I will post it in a while.
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