This is a binomial distribution with p = 0.14 (probability of each Nissan requiring warranty), k = 2 (two Nissans require warranty) and n = 14 (sample size of 14).
So P(k=1) is given by the binomial distribution pdf which is:
P(k) = (n choose k) p^k (1-p)^(n-k)
= n! / [ k!(n-k)! ] x p^k (1-p)^(n-k)
= 14! / [2! x 12!] x 0.14^2 x 0.86^12
= 14x13/2 x 0.0196 x 0.163675
= 0.2919 to 4 decimal places
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