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if possible.
1- 3c^2 - 33c + 72
2- 2y^5 + 13y^4 + 6y^3
3- 3u^8 - 13u^7 + 4u^6
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Explanation & Answer
1- 3c^2 - 33c + 72
= 3(c^2-11c+24)
= 3(c-8)(c-3)
2- 2y^5 + 13y^4 + 6y^3
= y^3(2y^2+13y+6)
= y^3(2y+1)(y+6)
3- 3u^8 - 13u^7 + 4u^6
= u^6(3u^2-13u+4)
= u^6(3u-1)(u-4)
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