if possible.

1- 3c^2 - 33c + 72

2- 2y^5 + 13y^4 + 6y^3

3- 3u^8 - 13u^7 + 4u^6

= 3(c^2-11c+24)

= 3(c-8)(c-3)

= y^3(2y^2+13y+6)

= y^3(2y+1)(y+6)

= u^6(3u^2-13u+4)

= u^6(3u-1)(u-4)

Secure Information

Content will be erased after question is completed.

Enter the email address associated with your account, and we will email you a link to reset your password.

Forgot your password?

Sign Up