The width of a rectangular slab of concrete is 3 m less than the length. The area is 28 m^2.
a) What are the dimensions of the rectangle?
b)What is the perimeter of the rectangle?
math1.docx Area of Rectangle = Length * Width
This implies that
X * (X-3) = 28
Expand the equation
X^2 - 3x =
X^2 - 3x
- 28 = 0
Solving by factorization
X^2 - 7x +
4x -28 = 0
X(X - 7) 4(X- 7) = 0
(X+4) (X-7) = 0
X=-4 or X=7
Since we cannot have a negative value for length ‘x’
If the Length X= 7, then the Width = (7-3)=4
A) Dimension = 7m by 4m (Length by Width)
B)Perimeter = 2 (Length + Width)
Perimeter = 2 ( 7
Perimeter = 2 (11)
Perimeter = 22
Length * Width = 28
7 * 4 = 28
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