In a physics experiment, a ball is dropped off a 144-ft platform. The height of the ball above the ground is given by the equation.

H= -16t^2 + 144 where H is the ball's height in feet, and t is the time in second after ball is drop (t _>0)

(Hint:h=0)

Answer:

using your data, we can compute the time T at which your ball hits the ground, using this formula:

T = sqrt (2 * H /g) = sqrt(2 * 144 / 32.2) = 2.92 seconds, I have assumed that the gravity g = 32.2 feet/seconds^2

then the magnitude of the velocity V is:

V = g*T = 32.2 * 2.99 = 96.28 feet/second.

Alternatively, in order to get the value for V, we can use the Torricelli's formula:

V = sqrt (2*g*H) = sqrt(2 * 32.2 * 144) = 96.29 feet/second

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