In a physics experiment, a ball is dropped off a 144-ft platform. The height of the ball above the ground is given by the equation.
H= -16t^2 + 144 where H is the ball's height in feet, and t is the time in second after ball is drop (t _>0)
using your data, we can compute the time T at which your ball hits the ground, using this formula:
T = sqrt (2 * H /g) = sqrt(2 * 144 / 32.2) = 2.92 seconds, I have assumed that the gravity g = 32.2 feet/seconds^2
then the magnitude of the velocity V is:
V = g*T = 32.2 * 2.99 = 96.28 feet/second.
Alternatively, in order to get the value for V, we can use the Torricelli's formula:
V = sqrt (2*g*H) = sqrt(2 * 32.2 * 144) = 96.29 feet/second
Content will be erased after question is completed.
Enter the email address associated with your account, and we will email you a link to reset your password.
Forgot your password?