Small Sample Estimation of a Population Mean


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Mar 11th, 2015

Since we don't know the population standard deviation, only that for the sample, we should use a t-distribution here, with df = n-1 = 24. The critical t-stat for a 98% confidence interval will be:

t_crit = t.inv(p=0.99,df=24) = 2.492159473

The standard error is sample sd / sqrt(n) = 8/sqrt(25)

SEM = 1.6

So the 98% confidence interval for the sample mean is given by 

sample mean +/- t_crit x SEM

= 173 +/- 2.492159473 x 1.6

= [169.01 to 176.99]


Mar 11th, 2015

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Mar 11th, 2015
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Mar 11th, 2015
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