Since the highest exponential degreee of the equation is (3), then the equation has 3 zeros.We already know one of the zeros: (x-4). Thus, we must divide the equation in order to get new one. We will divide
After divinding, we get a new equation:
(2x^3 + 7x^2 - 53x - 28) / (x-4) using synthetic division
2x^2 + 15x + 7Now, we can use the quadratic formula to find the other 2 zeros.
We know that
We have found the three zeros:a= 2
- (x - 4)
- (x + 7)
- (x + 1/2)
The Rational Zero Theorem.
You need to list all the possible factors of p (6) and q (4).
Also, all the values of (p/q). [Take into account that there are duplicates, just cross them out]
Now, you must use synthetic division with all values of (p/q) in order to determine if they are zeros. For example, I will use synthethic division with (1/3).
As you can see, there is no remainder. Therefore, 1/3 is one of the equation's zeros. You do the work for the other ones if you need it.
The three zeros for this equation are:
- (x - 1/3)
- (x - 1)
- (x + 2)
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