# Solve the model without the auxiliary variables

Anonymous
timer Asked: Aug 21st, 2017
account_balance_wallet \$30

Question description

PLEASE PLEASE I KNOW YOU PROBABLY ALREADY KNOW WHAT TO DO BUT BE AS CLOSE AS POSSIBLE TO THE RUBRIC AND EXAMPLE BELOW PLEASE!!!! I NEED GOOD GRADE

13-7.  Klein Industries manufactures three types of portable air compressors: small, medium, and large, which have unit profits of \$20.50, \$34.00, and \$42.00, respectively. The projected monthly sales are:

Small  Medium  Large

Minimum  14,000   6,200  2,600

Maximum  21,000  12,500  4,200

The production process consists of three primary activities: bending and forming, welding, and painting. The amount of time in minutes needed to process each product in each department is shown below:

Small  Medium  Large  Available Time
Bending/forming      0.4  0.7  0.8  23,400

Welding  0.6  1.0  1.2  23,400

Painting      1.4  2.6  3.1  46,800

How many of each type of air compressor should the company produce to maximize profit?

a.  Formulate and solve a linear optimization model using the auxiliary variable cells method and write a short memo to the production manager explaining the sensitivity information.

b.  Solve the model without the auxiliary variables and explain the relationship between the reduced costs and the shadow prices found in part a.

Solution Tip: You must use Solver tool in Excel. Set your constraints right, and fill in the solver dialogue box properly. Be sure to review links provided in the last lesson, or in one of the announcements in the first week of class. Here is a You Tube link you could view: http://www.youtube.com/watch?v=Oyc0k9kiD7o

SMDA5 03.ppt

## Tutor Answer

Prof_Holley
School: UIUC

Hey buddy!Attached is the assignment.Please have a look at it and feel free to seek any further clarification. I will revise any part part that you will want me to until you are 100% satisfied with the work. Thanks. 😉

LP_max

Linear, Integer and Mixed Integer Programming
Signs
<
=
>

less than or equal to
equals (You need to enter an apostrophe first.)
greater than or equal to

Data
S
M
L
Objective
\$ 20,50 \$ 34,00 \$ 42,00 sign
Min Demand for Small
1
>
Max Demand for Small
1
<
Min Demand for Medium
1
>
Max Demand for Medium
1
<
Min Demand for Large
1>
Max Demand for Large
1<
Bending/Forming Constraint
0,4
0,7
0,8 <
Welding Constraint
0,6
1
1,2 <
Painting Constraint
1,4
2,6
3,1 <
Results
Variables
Objective

16157,1

6200

RHS
14000
21000
6200
12500
2600
4200
23400
23400
46800

2600
\$ 651.221,43

Page 1

Results
LHS
651221
16157,1
16157,1
6200
6200
2600
2600
12882,9
19014,3
46800

Problem setup area
Slack/Surplus
-2157,14
4842,86
0
6300
0
1600
10517,1
438...

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Review

Anonymous
Excellent job

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