The standard enthalpy of vaporization for CHF_{2}Cl is 233.59 J/g at its normal boiling point of -40.75°C.

Answer to the nearest 0.1 J K^{-1} mol^{-1}.

Again, we use G = H - TS

H = 233.59 J/g

T = -40.75 + 273 = 232.25 K

G = 0

So essentially we have H = TS, solving for S....

S = H / T = (233.59 J/g) / (232.25 K) =

1.0 J/K/g

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