 Science
chem easy question, for best answer, just need part C

### Question Description  As you know rate of consumption is equal to k*([A]^a)*([B]^b) for the reaction a*A+b*B->c*AB. In your case rate = k*([NO]^2)*([Cl2]^2). Using your table row 3 we get rate = 5.0*(10^(-3)) = k*(0.13^2)*(0.10). When both reactants have concentration of 0.12M rate will be k*(0.12^2)*(0.12). Using previous equation we get rate of 5.0*(10^(-3))*(0.12^2)*(0.12)/((0.13^2)*(0.10))=5.11*10^(-3) M/s. This is the answer. Boston College Anonymous
I was on a very tight deadline but thanks to Studypool I was able to deliver my assignment on time. Anonymous
The tutor was pretty knowledgeable, efficient and polite. Great service! Anonymous
Heard about Studypool for a while and finally tried it. Glad I did caus this was really helpful. Studypool 4.7 Trustpilot 4.5 Sitejabber 4.4 Brown University

1271 Tutors California Institute of Technology

2131 Tutors Carnegie Mellon University

982 Tutors Columbia University

1256 Tutors Dartmouth University

2113 Tutors Emory University

2279 Tutors Harvard University

599 Tutors Massachusetts Institute of Technology

2319 Tutors New York University

1645 Tutors Notre Dam University

1911 Tutors Oklahoma University

2122 Tutors Pennsylvania State University

932 Tutors Princeton University

1211 Tutors Stanford University

983 Tutors University of California

1282 Tutors Oxford University

123 Tutors Yale University

2325 Tutors