How many g of sulfur, S8, must be dissolved in 100.0 g naphthalene, C10H8, to ma

Question Description

I don’t know how to handle this Chemistry question and need guidance.

How many g of sulfur, S8, must be dissolved in 100.0 g naphthalene, C10H8, to make a 0.15 

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Final Answer

The statement of the problem seems to be incomplete. It looks line the 0.15 is the molality of the solution.

Then 0.15 = x mol of S_8 / 100.0 g of solvent, so that x = 0.015 mol of S_8.

To find the mass of sulfur S_8, multiply the number of moles by its molar mass:

0.015 mol * (8*32.06) g/mol = 3.8 g.

Note: In order to find the answer in case when 0.15 represents the molarity of the solution or other concentration unit we should know the density of the solution.

repet22 (1096)
Carnegie Mellon University

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