623.1g/1329g =

mass percent is thus 0.4681x100 = 46.81 % H2SO4.

First, calculate the mass of solvent: mass of solvent = mass of solution – mass of H2SO4 = (density x volume) of solution – mass of H2SO4 = (1.329 kg/L x 1L) solution – 0.6231 kg of H2SO4 = 0.7059 kg of solvent

mole of H2SO4=623.1/98.09=6.352 mol fraction

molarity=6.352/0.7059=8.998 m H2SO4

Molarity in Solution=6.352/1L Soln=6.352 M H2SO4

those were all wrong on my webassign

i need exact answer

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