Please answer question below

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Mar 13th, 2015

623.1g/1329g = 

mass percent is thus 0.4681x100 = 46.81 % H2SO4. 

First, calculate the mass of solvent: mass of solvent = mass of solution – mass of H2SO4 = (density x volume) of solution – mass of H2SO4 = (1.329 kg/L x 1L) solution – 0.6231 kg of H2SO4 = 0.7059 kg of solvent 

mole of H2SO4=623.1/98.09=6.352 mol fraction

molarity=6.352/0.7059=8.998 m H2SO4

Molarity in Solution=6.352/1L Soln=6.352 M H2SO4



Mar 13th, 2015

those were all wrong on my webassign

Mar 13th, 2015

those were all wrong on my webassign

Mar 13th, 2015

those were all wrong on my webassign

Mar 13th, 2015

i need exact answer

Mar 13th, 2015

i need exact answer

Mar 13th, 2015

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