answer pic for chemistry

Chemistry
Tutor: None Selected Time limit: 1 Day

Mar 13th, 2015

a) Volume of solution = 550 mL = 0.550 L; molarity = 0.217 M

The amount of the solute = 0.550 L * 0.217 mol/L = 0.119 mol

b) The molality of solution is 0.175 m. It means that 0.175 mol of KCl is dissolved in 1 kg of water. 

1 mol of KCl = 39.10 + 35.45 = 74.55 g of KCl. (use the periodic table for atomic masses of K and Cl)

Then 0.175 mol  contain  0.175 * 74.55 = 13.0 g of KCl.  The total mass of solution is 1.013 kg. 

From the proportion 0.175 mol / 1.013 kg = x mol / 0.0818 kg we find that x = 0.175 *0.0818/1.013 = 0.141 mol 

c) The mass of the solute (glucose) is 120.0 g * 6.75% = 8.1 g, however, we need to find the number of moles. Since the molar mass of C6H12O6 is 6*12.011+12*1.008+6*16 = 180 g/mol, the number of moles is 

8.1 g / 180 g/mol = 0.045 mol

Mar 13th, 2015

Are you studying on the go? Check out our FREE app and post questions on the fly!
Download on the
App Store
...
Mar 13th, 2015
...
Mar 13th, 2015
Dec 9th, 2016
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer