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Chemistry
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Mar 13th, 2015

623.1g/1329g = 

mass percent is thus 0.4681x100 = 46.81 % H2SO4. 

First, calculate the mass of solvent: mass of solvent = mass of solution – mass of H2SO4 = (density x volume) of solution – mass of H2SO4 = (1.329 kg/L x 1L) solution – 0.6231 kg of H2SO4 = 0.7059 kg of solvent 

mole of H2SO4=623.1/98.09=6.352 mol fraction

molarity=6.352/0.7059=8.998 m H2SO4

Molarity in Solution=6.352/1L Soln=6.352 M H2SO4


Mar 13th, 2015

it said a and b are incorrect

Mar 13th, 2015

how i calculated myself

Mar 13th, 2015

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