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answer for chemistry

Chemistry
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Mar 13th, 2015

a) Molar mass of Mg(NO3)2 = 24.31 + 2*14.01 + 6*16.00 = 148.33 g/mol

The amount of magnesium nitrate in moles: 0.523 g / 148.33 g/mol = 0.00353 mol

The molarity is 0.003526 mol / 0.2350 L = 0.0150 M.

b) The molar mass of LiClO4 3H2O = 6.94 + 35.45 + 4*16.00 + 3(2*1.008+16.00) = 160.4 g/mol

The number of moles of the solute is 20.2 g / 160.4 g/mol = 1.259 mol.

The molarity if 1.259 mol / 0.230 L = 5.47 M.

c) The original solution contained 0.0400 L * 2.64 mol/L = 0.106 mol of HNO3. After it is diluted to 0.390 L 

the molarity becomes 0.106 mol / 0.390 L = 0.272 M.


Mar 13th, 2015

thanks its all right except this one

Mar 13th, 2015
screen_shot_2015_03_13_at_12.15.59_pm.png

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