Normal distribution central limit theorem

Question Description

An  average number of hours that a kid spends per day working At a computer is3.5 hours with a STDV of 0.9 hours.Whats the probability that a randomly selected sample of 12 kids tospend an average of more than 3.8 hours per day working on a computer?

Final Answer

xbar =3.8

mu =3.5

sigma =0.9

n =12

z = (3.8-3.5)/(0.9/sqrt(12)) = 0.3 *sqrt(12)/0.9 = 1.15

P(z> 1.45) =0.1251

Answer: 0.1251 or 12.51%

madhavant (2757)
Boston College

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