a survey of people reported that 55% of people said they had been in a tornado. How many people must be surveyed this year to estimate the percentage of people to be 95% confident that our estimate is within 5% of the true population percentage?
margin of error = 0.05
95% value =1.96
1.96 *sqrt(0.55*0.450/sqrt(n) =0.05
sqrt(n) = 1.96 *sqrt(0.55*0.45)/0.05 =1.96 *0.497494/0.05 =0.975088/0.05 =19.50
n =19.50^2 =380.3184 =381
sample size needed =381
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