How much iron is present in 6.59 g of iron(III)
Answer in units of g.
atomic mass of Fe = 55.8 g/mole
atomic mass of O = 15.99 g/mole
molar mass of Fe2O3 = 55.8 X 2 + 15.99 X 3 = 111.6 + 47.97 = 159.57 g/mole
so in 159.57 g of Fe2O3 there are 111.6 g of Fe
so in 6.59 g of Fe2O3 there will be 111.6/159.57 X 6.59 = 4.609 g of FePlease select my answer as the best if it was helpful to you. Thanks :)
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