How many atoms of carbon are present in
12.9 g of a compound that is 36.7% carbon, by
Answer in units of atoms.
36.7 % of 12.9 g = 4.73 g - the mass of carbon in the sample
4.73 g / 12.011 g/mol = 0.394 - the amount of carbon in moles
Multiplying the latter by the Avogadro's number, obtain 0.394 * 6.022 * 10^23 = 2.37 times 10^23 atoms of C.
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