 Mathematics
polynomial dont know how to appile formula

### Question Description

x^3+12x^2+13x=x   solve for x First simplify: x^3  + 12x ^2 + 13x -x = 0

x^3 + 12x^2 + 12x =0

Take out x as a common factor x (x^2 + 6x + 6) =0

One solution is x=0

To get the other apply quadratic formula with a = 1 b = 6 and c =6 to get

[-6 +/- Sqr (6 ^2 - 4 *1 * 6)]/ 2*1

[-6 + Sqr (12)]/2  or [-6 - Sqr (12)]/2

which simplifies to -3 + Sqr 3    and -3 -Sqr3 John Si. (970)
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