P(x) = x^4 - 3x^2 - 4= x^4 - 4x^2 +x^2 -4= x^2 ( x^2 - 4)+1(x^2 - 4)=(x^2 +1)(x^-4)=(x^2 + 1)(x+2)(x-2)to find the zeros,(x^2+1)(x+2)(x-2) =0x^2+1 = 0 or x+2 =0 or x -2=0x^2 = -1 or x=-2 or x=2x= sqrt(-1)= i or x =-2 or x =2x = i, -2 and 2Please best my answer if it was helpful to you.

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