x^2+8x+6 (x^2+8x+)+6 erin was completing the sqaure of the

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quadratic function in order to find the extreme value. what is the next step. what is the extreme value?

(x+8)^2=58;the extreme minimum is -8

(x+4)^2 -10;the extreme minimum is -4

(x^2+8x+16) +6 -16;the extreme mini is -10

(x^2+8x+64)+6-64;the ex min-58

Mar 15th, 2015

(x^2+8x+16) +6 -16;the extreme mini is -10


Please select my answer as best i helpful. Thanks

Mar 15th, 2015

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