Given cotθ = ((-√105)/8), find the exact value of sin2θ

label Calculus
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Assume (3π)/2 < θ < 2π

Mar 17th, 2015

cot(theta) is negative in the 2nd and 4th quadrants,

So, sin(theta) = 8 / 13   and cos(theta) = - sqrt(105) / 13

sin2(theta) = 2sin(theta)cos(theta)

= 2(8/13)(-sqrt(105)/13) = - 16sqrt(105) / 169

Mar 17th, 2015

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