Britta bought some carrots and apples for $24.80. A carrot and an apple cost $0.90 altogether. She bought more carrots than apples. the cost of the extra number of carrots was $6.80. How many apples did Britta buy?

Let x = number of carrot

Let y = number of apples

Let C = cost per carrot

Let A = cost per apple

xC + yA = 24.80

C + A = 0.90 so A = 0.90 - C

C(x-y) = 6.80

C = 6.8 / x-y

xC + y(0.9 - C) = 24.8

x(6.8 / x-y) + y(0.9 - 6.8 / x-y) = 24.8

6.8(x-y)/(x-y) + 0.9y = 24.8

6.8 + 0.9y = 24.8

0.9y = 18

y = 20

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