Time remaining:
What is the initial velocity of the marble as it leaves the launching device?

label Physics
account_circle Unassigned
schedule 0 Hours
account_balance_wallet $5

A marble is fired horizontally from a launching device attached to the edge of a tabletop which is 94.0 cm above the floor. The marble then strikes the floor 2.35 meters from the edge of the table. Show your work please.

Oct 9th, 2014

Choose the plane coordinates system centered at the initial position of the marble with the x-axis directed to the right and the y-axis directed downwards.

Let x, y be the coordinates of the point where the marble hit the floor and t be the time when it happened.

Given: x = 2.35 m, y = 94.0 cm = 0.940 m, g = 9.81 m/s^2.

Find the initial velocity v.

From the equations x = vt and y = gt^2/2 we find t = sqrt{2y/g} and v = x/t = x sqrt{g/2y} =

2.35 * sqrt{9.81/(2*0.940)} = 5.37 m/s 

Mar 18th, 2015

Did you know? You can earn $20 for every friend you invite to Studypool!
Click here to
Refer a Friend
...
Oct 9th, 2014
...
Oct 9th, 2014
Jun 25th, 2017
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer