A student brought 25.50 g of iron ( Cp = 0.449 J/(g°C)) at 23.8°C into contact with 54.44 g of silver ( Cp = 0.235 J/(g°C)) at 70.5°C. Determine the equilibrium temperature ( to 0.1 °C)
for iron, q= 25.5*0.449x=11.45x
for silver, q=54.44*0.235x1=12.79x1
Tf= 44.08= 44.1 degree celcius.......................
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