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What is the dimensions of 100 square feet and 401 perimeter

label Mathematics
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Mar 19th, 2015

Let the length is L & width is W

hence area, L×W=100;  or,     L= 100/W

Perimeter , 2 (L+W)=401

We can substitute value of  L from above we get

2 (100/W +W)=401

Solving we get


We can write it as


Or we can get 2w (w-200)-1 (w-200)=0

Or we get, (w-200)(2w-1)=0

Hence we get w=200 or w=0.5

Substituting l=100/200= 0.5

Hence dimensions are 


200 ft length and 

width= 0.5 ft

Mar 19th, 2015

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