I don't know this and this homework

Let the length is L & width is W

hence area, L×W=100; or, L= 100/W

Perimeter , 2 (L+W)=401

We can substitute value of L from above we get

2 (100/W +W)=401

Solving we get

2w^2-401w+200=0

We can write it as

2w^2-400w-w+200=0

Or we can get 2w (w-200)-1 (w-200)=0

Or we get, (w-200)(2w-1)=0

Hence we get w=200 or w=0.5

Substituting l=100/200= 0.5

Hence dimensions are

Answer

200 ft length and

width= 0.5 ft

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