A teacher is traveling at 8 m/s (Va1) when he (Mass A=100 kg) runs into a student (Mass B=100) who is standing still (Vb1 =0). If the teacher is traveling at 3 m/s (VA2) after the crash, how fast is the student traveling at (VB2)?

Use the conservation of momentum: M_A * V_{a1} + M_B * V_{b1} = M_A * V_{a2} + M_B * V_{b2}.

Then 100 * 8 + 100 * 0 = 3 * 100 + 100 * V_{b2}, and V_{b2} = 8 - 3 = 5 m/s is the answer.

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