2Cu+(aq) + Pb(s) → Pb2+(aq) + 2Cu(s)
= - ΔG0rxn
/ nF = (F = 96500 C/mol, n = 2)
124.7*1000 J/mol / (2*96500 C/mol) = 0.646 V
Content will be erased after question is completed.
Enter the email address associated with your account, and we will email you a link to reset your password.
Forgot your password?