Find all solutions in the interval [0,2π)

Question Description

I don’t know how to handle this Calculus question and need guidance.

sin^2(theta) + cos(theta) = 1

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Final Answer

1-cos^2(theta) +cos(theta) = 1

cos(theta) (cos(theta)-1) = 0 

cos theta = 0 or cos theta = 1

for cos theta =0 we have solution 

theta = pi/2 or theta = 3pi/2

for cos theta = 1  we have 

theta = 0.  

JamesM847 (3822)
Cornell University

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