Find all solutions in the interval [0,2π)

Calculus
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sin^2(theta) + cos(theta) = 1

Mar 20th, 2015

1-cos^2(theta) +cos(theta) = 1

cos(theta) (cos(theta)-1) = 0 

cos theta = 0 or cos theta = 1

for cos theta =0 we have solution 

theta = pi/2 or theta = 3pi/2

for cos theta = 1  we have 

theta = 0.  


Mar 20th, 2015

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