Time remaining:
##### i need to find the awnser for this question

label Algebra
account_circle Unassigned
schedule 1 Day
account_balance_wallet \$5

Oct 20th, 2017

if the volume of sphere is = volume of all the four container than without wasting a single drop all the four will be filled till their mouth

height of big container = sqrt [(4.2 pi )^2-(2.6pi)^2] = 10.88 pi

Volume of Biggest container  = Pi r^2*h = pi * (1.3 pi)^2* 10.88 pi= 18.3872 pi^3

since dilation factor is 0.5 hence radius and height will be half of previous one
. hence volume will be 1/8 of previous

therefore volume of second container = 1/8 *18.3872 pi^3 = 2.2984 pi^3

volume of third  container = 1/8 *2.2984 pi^3 = 0.2873 pi^3

volume of last container = 1/8 *0.2873 pi^3 =0.03591 pi^3

hence total volume =21.008 pi^3

volume of sphere = 4/3  pi *r^3 = 21.008 pi^3

solving we get r^3 = 21.008*3/4 pi^3/pi

or r^3 = 15.756 pi^2 =155.3538

or radius , r = 5.3757

Mar 21st, 2015

...
Oct 20th, 2017
...
Oct 20th, 2017
Oct 21st, 2017
check_circle