if the volume of sphere is = volume of all the four container than without wasting a single drop all the four will be filled till their mouth
height of big container = sqrt [(4.2 pi )^2-(2.6pi)^2] = 10.88 pi
Volume of Biggest container = Pi r^2*h = pi * (1.3 pi)^2* 10.88 pi= 18.3872 pi^3
since dilation factor is 0.5 hence radius and height will be half of previous one . hence volume will be 1/8 of previous
therefore volume of second container = 1/8 *18.3872 pi^3 = 2.2984 pi^3
volume of third container = 1/8 *2.2984 pi^3 = 0.2873 pi^3
volume of last container = 1/8 *0.2873 pi^3 =0.03591 pi^3
hence total volume =21.008 pi^3
volume of sphere = 4/3 pi *r^3 = 21.008 pi^3
solving we get r^3 = 21.008*3/4 pi^3/pi
or r^3 = 15.756 pi^2 =155.3538
or radius , r = 5.3757
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