If a ball is thrown directly upward with a velocity of 24 ft/s, its height (in feet) after t seconds is given by y = 24t − 16t^{2}. What is the maximum height attained by the ball? (Round your answer to the nearest whole number.)

the maximum height is attained after 24/(2*16) = 0.75 s and equals y = 24*0.75 - 16*0.75^2 = 9 ft.

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