A soft-drink vendor at a popular beach analyzes his sales records and finds that

Algebra
Tutor: None Selected Time limit: 1 Day

P(x) = 0.001x2 + 3x − 1800.

What is his maximum profit per day?
 

How many cans must he sell for maximum profit?
 cans
Mar 22nd, 2015

The maximum profit will be achieved for x = 3/(2*0.001) = 1500 and equals

P(1500) = -0.001*1500^2 + 3*1500 - 1800 = -2250 + 4500 - 1800 = 450

Answer: $450; 1500 cans.

Mar 22nd, 2015

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