Statistics...........On Question # 3, consider a random sample X1, X2,… Xn from

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Mar 23rd, 2015

We know that MLE of lambda is xbar.

P0=P(x=0) = exp(-lambda)

MLE of P0 = exp(-xbar)

b)

mle of lambda =137/122=1.123

mle of P0 = exp(-137/122)=0.3253

c)

mle of 1-P0 = 1-exp(-137/122)=0.6747

Mar 23rd, 2015

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Mar 23rd, 2015
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Mar 23rd, 2015
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